1/5y^2+4/5y

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Solution for 1/5y^2+4/5y equation: 


y in (-oo:+oo)

(1/5)*y^2+(4/5)*y = 0

1/5*y^2+4/5*y = 0

DELTA = (4/5)^2-(0*1/5*4)

DELTA = 16/25

DELTA > 0

y = ((16/25)^(1/2)-4/5)/(1/5*2) or y = (-(16/25)^(1/2)-4/5)/(1/5*2)

y = 0 or y = -4

y in { -4, 0 }

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